package leetcode.problems;

import org.junit.Test;

/**
 * Created by gmwang on 2020/1/31
 * Find Numbers with Even Number of Digits
 * 查找具有偶数位数的数字
 */
public class FindNumberswithEvenNumberofDigits {
    /**
     * Given an array nums of integers, return how many of them contain an even number of digits.
     * 鉴于num的整数数组,返回其中包含偶数个多少位数。
     *
     * Example 1:
     *
     * Input: nums = [12,345,2,6,7896]
     * Output: 2
     * Explanation:
     * 12 contains 2 digits (even number of digits).
     * 345 contains 3 digits (odd number of digits).
     * 2 contains 1 digit (odd number of digits).
     * 6 contains 1 digit (odd number of digits).
     * 7896 contains 4 digits (even number of digits).
     * Therefore only 12 and 7896 contain an even number of digits.
     * Example 2:
     *
     * Input: nums = [555,901,482,1771]
     * Output: 1
     * Explanation:
     * Only 1771 contains an even number of digits.
     *
     *
     * Constraints:
     *
     * 1 <= nums.length <= 500
     * 1 <= nums[i] <= 10^5
     **/
    public int findNumbers(int[] nums) {
        int result = 0;
        for (int i = 0; i < nums.length; i++) {
            if((String.valueOf(nums[i]).length()&1) != 1){
                result ++;
            }
        }
        return result;
    }
    @Test
    public void test(){
//        int [] nums = {12,345,2,6,7896};
        int [] nums = {555,901,482,1771};
        int numbers = findNumbers(nums);
        System.out.println(numbers);
    }
}
